Answer:
The Amplitude is 7.34 × 10^6m
Explanation: complete question(The ultrasonic transducer used in a medical ultrasound imaging device is a very thin disk (m = 0.10 g) driven back and forth in SHM at 1.0 MHz by an electromagnetic coil.)
From Newton's 2nd law, the force F on a body with mass,m is related to its acceleration by:
F= ma ...eq1
The maximum transverse speed and acceleration of a particle in simple Harmonic motion are found in terms of the angular speed and amplitude
Vmax=wa ...eq2
amax= w^2A ...eq3
The angular frequency w of a wave is related to the frequency by:
w = 2pif ...eq4
Fmax= mw^2A
Fmax= m(2pif)^2A
Fmax= 4pi^2mf^2A
Where Fmax= maximum restoring force
m= mass of disk
f= frequency of disk
A= Fmax/[4pi^2×(0.10×10^-3)×(1.0×10^6)^2]
A= 29000/ [4x(3.142)^2×(0.10×10^-3)×(1.0×10^6)^2]
A= 29000/(3948865600)
A= 7.34×10^-6m