Answer:
a) x = 660 m , b) λ = 0.330 m , c) precision is 0.1 cm , d) Δf= n Δt/ t²
Step-by-step explanation:
a) the speed of sound is constant, therefore we can use the relation of motion to inform the distance that the sound extends is
v = x / t
x = v t
x = 330 2
x = 660 m
b) the speed of sound is
v = λ f
λ = v / f
λ = 330/1000
λ = 0.330 m
c) a measuring tape must be used to measure the wavelength, the precision is 0.1 cm
.d) frequency measurement is more delicate, a stopwatch should be used to measure a certain number of oscillations, and hence calculate the frequency
.f = n / t
Therefore, if we assume that there is no error in the number of oscillations, the pressure is given by the appreciation of the stopwatch, which is maximum 0.01 s
Δf / f = Δt / t
Δf = Δt /t f
Δf= n Δt/ t²