Yes, the partition gives the two brothers equal shares.
Explanation:
Step 1:
Assume the entire field has an area of B. So one brother takes
,
, and
So we need to calculate how much this brother takes in terms of B.
To do this we calculate how much
is.
Step 2:
To add
,
First take the LCM of the denominators 12, 6, and 4
The LCM is 12, we multiply the denominator to get the LCM value, this same value is multiplied to the numerator too.

Step 3:
One brother gets
, so we need to calculate how much the other brother gets.
The other brother's share =

So both the brothers get equal shares