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Determine the quotient of the complex numbers 3 + 4i and 8 - 2i, using the latter as the divisor.

User ByJeevan
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1 Answer

3 votes

Answer:


(4)/(17) +(19)/(34)i

Explanation:


(3+4i)/(8-2i) = ((3+4i)(8+2i))/((8-2i)(8+2i)) =(24+6i+32i-8)/(64+4) =(16+38i)/(68) =(4)/(17) +(19)/(34)i

User FIwJlxSzApHEZIl
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