Question

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in the mixture. (Enter unrounded values.)

Answer 1

Answer: The concentration of X is
`7.13582* 10^(-6)` and the concentration of Y is
`2.53159* 10^(-5)`.

Explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

`16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191`

By solving these two equations, we get that

`C_1=7.13582* 10^(-6)\\\\C_2=2.53159* 10^(-5)`

Hence, the concentration of X is
`7.13582* 10^(-6)` and the concentration of Y is
`2.53159* 10^(-5)`.