Question

What is the electric potential energy of an electron at the negative end of the cable, relative to the positive end of the cable? In other words, assume that the electric potential of the positive terminal is 0 V and that of the negative terminal is −12V. Recall that e=1.60×10−19C.

Answer 1

Step-by-step explanation:

charge of electron, e = 1.6 x 10^-19 C

V1 = 0 V

V2 = -12 V

Change in potential, ΔV = V1 - V2 = 0 - ( - 12) = 12 V

potential energy, U = q x ΔV

U = 1.6 x 10^-19 x 12

U = 1.92 x 10^-18 J