Question

Calculate the velocity of electrons that form the same pattern as 450-nm light when passed through a double slit. The mass of an electron is 9.11 \times 10^{-31}~\text{kg}9.11×10 ​−31 ​​ kg.

Answer 1

The velocity of electrons is 1617.27 m/s.

Step-by-step explanation:

Given that,

Wavelength of light,
`\lambda=450\ nm=450* 10^(-9)\ m`

Mass of an electron,
`m=9.11* 10^(-31)\ kg`

We need to find the velocity of electrons. It can be given by using De-Broglie wavelength such that :

`\lambda=(h)/(mv)\\\\v=(h)/(m\lambda)\\\\v=(6.63* 10^(-34))/(9.11* 10^(-31)* 450* 10^(-9))\\\\v=1617.27\ m/s`

So, the velocity of electrons is 1617.27 m/s. Hence, this is the required solution.