Question

Calculate the change in enthalpy associated with the combustion of 492.2 g of sulfur.Report your answer with four significant figures.Do not include a comma in your answer.

Answer 1

The question is incomplete, complete question is :

Calculate the change in enthalpy associated with the combustion of 492.2 g of sulfur. Report your answer with four significant figures. Do not include a comma in your answer.

`S(s)+O_2(g)\rightarrow SO_2(g) ,\Delta H_C=-296.8 kJ/mol`

Answer:

-4,565 kJ the change in enthalpy associated with the combustion of 492.2 grams of sulfur.

Step-by-step explanation:

Enthalpy change when 1 mole of sulfur is combusted = -296.8 kJ

Mass of sulfur = 492.2 g

Moles of sulfur =
`(492.2 g)/(32 g/mol)=15.38 mol`

Enthalpy change when 15.38 moles of sulfur:

`-296.8 kJ* 15.38=-4,565.155 kJ\approx -4,565 kJ`

-4,565 kJ the change in enthalpy associated with the combustion of 492.2 grams of sulfur.