The slant asymptote of f(x)=x^2+3x-4/x is y=3x+1 Please select the best answer from the choices provided T F

asked Apr 12, 2021 158k views

5 votes

The slant asymptote of f(x)=x^2+3x-4/x is y=3x+1

Please select the best answer from the choices provided

T
F

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2 votes

Answer:

False!!

Explanation:

Rjanjic answered Apr 14, 2021

4.1k points

2 votes

Answer: False

Explanation:

$y=(x^2+3x-4)/(x)\quad =\quad x+3-(4)/(x)$

So, the slant asymptote is: y = x + 3

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