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5 votes
Find the Sin, Cos, and Tan of the following angle:

-45 degrees

i have my teachers work here but i just don’t know the explanation of how to solve it

pleasee explain to me how to do this like my tecaher did

Find the Sin, Cos, and Tan of the following angle: -45 degrees i have my teachers-example-1
User Be Kind
by
6.5k points

1 Answer

3 votes


$\sin 45^\circ=(-1)/(√(2) ), \ \cos45^\circ=(1)/(√(2) ), \ \ \tan 45^\circ=-1

Solution:

In the given right triangle,

θ = 45°

Opposite side to θ = –1

Adjacent side to θ = 1

Hypotenuse =
√(2)

Using basic trigonometric ratio formulas,


$\sin \theta=\frac{\text { Opposite }}{\text { Hypotenuse }}


$\sin 45^\circ=(-1)/(√(2) )


$\cos \theta=\frac{\text { Adjacent }}{\text { Hypotenuse }}


$\cos45^\circ=(1)/(√(2) )


$\tan \theta=\frac{\text { Opposite }}{\text { Adjacent }}


$\tan 45^\circ=(-1)/(1)=-1

Therefore,


$\sin 45^\circ=(-1)/(√(2) ), \ \cos45^\circ=(1)/(√(2) ), \ \ \tan 45^\circ=-1

User Mahendran Kandiar
by
6.7k points
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