Question

lways use significant figure rules. Remember that these rules apply to all numbers that are measurements. Calculate the conductance of a conduit whose cross-sectional area is 3.0 cm2 and whose length is 14 cm if its conductivity is 0.90 ohm-1-cm-1. G = _____ ohm-1 5.2 0.19 0.58 0.24

Answer 1

0.19

Step-by-step explanation:

Answer 2

`0.19 \Omega^(-1)`

Step-by-step explanation:

For a wire, the conductance of the wire is given by:

`G=(\sigma A)/(L)`

where:

`\sigma` is the conductivity of the material

A is the cross-sectional area of the wire

L is the length of the wire

For the wire in this problem, we have:

`\sigma=0.90 \Omega^(-1) cm^(-1)` is the conductivity

`A=3.0 cm^2` is the cross-sectional area

`L=14 cm` is the length of the wire

Substituting the values into the equation, we find the conductance:

`G=((0.90)(3.0))/(14)=0.19 \Omega^(-1)`