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lways use significant figure rules. Remember that these rules apply to all numbers that are measurements. Calculate the conductance of a conduit whose cross-sectional area is 3.0 cm2 and whose length is 14 cm if its conductivity is 0.90 ohm-1-cm-1. G = _____ ohm-1 5.2 0.19 0.58 0.24

User Rlb
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2 Answers

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Answer:

0.19

Step-by-step explanation:

User James Carnegie
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Answer:


0.19 \Omega^(-1)

Step-by-step explanation:

For a wire, the conductance of the wire is given by:


G=(\sigma A)/(L)

where:


\sigma is the conductivity of the material

A is the cross-sectional area of the wire

L is the length of the wire

For the wire in this problem, we have:


\sigma=0.90 \Omega^(-1) cm^(-1) is the conductivity


A=3.0 cm^2 is the cross-sectional area


L=14 cm is the length of the wire

Substituting the values into the equation, we find the conductance:


G=((0.90)(3.0))/(14)=0.19 \Omega^(-1)

User Okema
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