Answer : The molarity of the chloride ion in the water is, 5.75 M
Explanation :
As we are given that 16.6 % chloride ion that means 16.6 grams of chloride ion present 100 grams of solution.
First we have to calculate the volume of solution.
![\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}](https://img.qammunity.org/2021/formulas/chemistry/college/xrnly0n4lqpwxmfqhtqcrnplogut2wp4b3.png)
![\text{Volume of solution}=(100g)/(1.23g/mL)=81.3mL](https://img.qammunity.org/2021/formulas/chemistry/college/peqhy71uj6js9p31lfyyua5k8g45n2cxzp.png)
Now we have to calculate the molarity of chloride ion.
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
![\text{Molarity}=\frac{\text{Mass of chloride ion}* 1000}{\text{Molar mass of chloride ion}* \text{Volume of solution (in mL)}}](https://img.qammunity.org/2021/formulas/chemistry/college/72vku8n4395941qbip616o3b0ciuk41k5r.png)
Now put all the given values in this formula, we get:
![\text{Molarity}=(16.6g* 1000)/(35.5g/mole* 81.3mL)=5.75mole/L=5.75M](https://img.qammunity.org/2021/formulas/chemistry/college/2qh0mphr71w4fx5cquj3dvab7dod6z6c1f.png)
Thus, the molarity of the chloride ion in the water is, 5.75 M