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Analysis of the water content of a lake found in the desert showed that it contained 16.6 percent chloride ion, and had a density of 1.23 g/mL. What is the molarity of the chloride ion in the water

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Answer : The molarity of the chloride ion in the water is, 5.75 M

Explanation :

As we are given that 16.6 % chloride ion that means 16.6 grams of chloride ion present 100 grams of solution.

First we have to calculate the volume of solution.


\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}


\text{Volume of solution}=(100g)/(1.23g/mL)=81.3mL

Now we have to calculate the molarity of chloride ion.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :


\text{Molarity}=\frac{\text{Mass of chloride ion}* 1000}{\text{Molar mass of chloride ion}* \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:


\text{Molarity}=(16.6g* 1000)/(35.5g/mole* 81.3mL)=5.75mole/L=5.75M

Thus, the molarity of the chloride ion in the water is, 5.75 M

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