Question

A 2.0 kg block, initially moving at 10.0 m/s, slides 50.0 m across a sheet of ice beforecoming to rest. What is the magnitude of the average frictional force on the block?

Answer 1

The magnitude of the average frictional force on the block is 2 N.

Step-by-step explanation:

Given that.

Mass of the block, m = 2 kg

Initial velocity of the block, u = 10 m/s

Distance, d = 50 m

Finally, it stops, v = 0

Let a is the acceleration of the block. It can be calculated using third equation of motion. It can be given by :

`v^2-u^2=2ad`

`-u^2=2ad`

`a=(-u^2)/(2d)\\\\a=(-(10\ m/s)^2)/(2* 50\ m)\\\\a=-1\ m/s^2`

The frictional force on the block is given by the formula as :

F = ma

`F=2\ kg* (-1)\ m/s^2\\\\F=-2\ N`

|F| = 2 N

So, the magnitude of the average frictional force on the block is 2 N. Hence, this is the required solution.