Question

How many solutions does the system have? \begin{cases} y = -2x-4 \\\\ y = 3x+3 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ y=−2x−4 y=3x+3 ​ How many solutions does the system have? \begin{cases} y = -2x-4 \\\\ y = 3x+3 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ y=−2x−4 y=3x+3 ​ How many solutions does the system have? \begin{cases} y = -2x-4 \\\\ y = 3x+3 \end{cases} ⎩ ⎪ ⎪ ⎨ ⎪ ⎪ ⎧ ​ y=−2x−4 y=3x+3 ​

Answer 1

Exactly ONE solution

Answer 2

x = -7/5 y = -6/5

Explanation:

System:

y = -2x-4

AND

y= 3x+3

therefore -2x-4 = 3x+3

-2x-3x = 3 + 4

-5x = 7

x = -7/5

y = 3(-7/5) + 3 = -21/5 + 3 = -6/5