Question

When a mass of 24 g is attached to a certain spring, it makes 21 complete vibrations in 3.3 s. What is the spring constant of the spring? Answer in units of N/m.

Answer 1

Answer: 3.889N/m

Step-by-step explanation:

f=(1/2)*√k/m

f=n/t

f= 21/3.3=6.4Hz

6.4*2=√k/m

12.73=√k/m

12.73^2=k/m

162.0529=k/m

Since m=24g

Convert g to kg

m=24/1000

m=0.024kg

K=162.0529*0.024

K=3.889N/m