Answer:
Hi your question is incomplete but the two possible scenarios would be the probability of a randomly chosen license plate having repeated numbers or repeated letters since the repetitions of letters and numbers are allowed
- probability for a license plate with repeated numbers will be = 0.0056%
- probability for a license plate with repeated letters will be = 0.1%
Step-by-step explanation:
If each plate consists of 6 characters which includes 3 numbers and 3 letters
The total number of plates that can be formed using this combination ( including repetition of number and letters ) will be
possible occurrence of letters = 26 ( a - z )
possible occurrence of numbers = 10 ( 0 - 9)
number of letters given = 3
number of digits given = 3
Hence total possible occurrence of letters will be ( possible occurrence of letters³(number of letters given) )
= 26*26*26 = 17576
Total possible occurrence of numbers will be ( possible occurrence of numbers³(number of digits given))
= 10*10*10 = 1000
The total number of plates that can be formed using the combination of 3 numbers followed by 3 letters will be
= 17576 * 1000 = 17576000
probability of repeated numbers = 1000 / 17576000 = 0.0056%
probability of repeated letters = 17576 / 17576000 = 0.1 %