Question

Find the density of seawater at a depth where the pressure is 680 atm if the density at the surface is 1030 kg/m3. Seawater has a bulk modulus of 2.3 × 109 N/m2. Bulk modulus is defined to be

B ≡ rho0 ∆P ∆rhoAnswer in units of kg/m3.

Answer 1

`1060.41kg/m^3`

Step-by-step explanation:

Bulk modulus is defined as the relative change in the volume of a body produced by a unit of compressive acting uniformly over its surface:

`B=\rho _o (\bigtriangleup P )/(\bigtriangleup \rho)`

Hence the density of the seawater at a depth of 680atm is calculated as:-

`\rho=\rho_o +\bigtriangleup \rho=\rho_o(1+(\bigtriangleup P)/(B))\\\\=1030 * (1+ ((680-1)*10^5)/(2.3* 10^9))\\=1060.41kg/m^3`