Question

2 SO2(g) + O2(g) 2 SO3(g) Assume that Kc = 0.0680 for the gas phase reaction above. Calculate the corresponding value of Kp for this reaction at 84.5°C.

Answer 1

Answer: The corresponding value of
`K_p` for this reaction at 84.5°C is 0.00232

Step-by-step explanation:

`2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)`

Relation of with is given by the formula:

`K_p=K_c(RT)^(\Delta ng)`

where,

= equilibrium constant in terms of partial pressure = ?

`K_c` = equilibrium constant in terms of concentration = 0.0680

R = Gas constant =
`0.0821\text{ L atm }mol^(-1)K^(-1)`

T = temperature =
`84.5^0C=(273+84.5)K=357.5K`

`\Delta n_g` = change in number of moles of gas particles =
`n_(products)-n_(reactants)=2-3=-1`

Putting values in above equation, we get:

`K_p=0.0680* (0.0821* 357.5)^(-1)\\\\K_p=0.00232`

Thus the corresponding value of
`K_p` for this reaction at 84.5°C is 0.00232