Question

Lena draws a square with an area that is greater than the area of rectangle b what are two possible side lengths of lenas square? Explain

Answer 1

Step-by-step explanation:

Suppose the square Lena draws has the following dimensions:

`Side=L \\ \\ A_(s):Area \\ \\ \\ A_(s)=L^2`

For the rectangle we have:

`Base=L_(1) \\ \\ Height=L_(2) \\ \\ \\ A_(r)=L_(1)L_(2)`

Possibility 1. In order for the area of the square to be greater than the area of the rectangle, the following inequality must be true:

`\boxed{(L^2)/(L_(1)L_(2))>1}`

Possibility 2. If one side of the rectangle equals the side of the square, that is:

`L_(1)=L`

Then, in order for the area of the square to be greater than the area of the rectangle, the following inequality must be true:

`(L^2)/(LL_(2))>1 \\ \\ \boxed{(L)/(L2)>1}`