Question

What is the perimeter of an isosceles trapezoid whose base 1 is 39ft, base 2 is 27ft and height is 12ft

Answer 1

Explanation:

Given one is an isosceles trapezoid. Hence its non-parallel sides are equal.

In order to find the Perimeter of trapezoid, we need to find the length of non-parallel sides

Length of non-parallel sides can be obtained using Pythagoras theorem as given below:

`Length \: of \: non-parallel \: sides \\ = \sqrt{ {(diff. \: of \: bases)}^(2) + ({height)}^(2) } \\ = \sqrt{ {(39 - 27)}^(2) + {(12)}^(2) } \\ = \sqrt{ {12}^(2) + {12}^(2) } \\ = \sqrt{2 * {12}^(2) } \\ = 12 √(2) \\ = 12 * 1.414 \\ = 16.968 \\ = 16.97 \: ft \\ \\ perimeter \: of \: trapezoid \\= 39 + 27 + 2 * 16.97 \\ = 66 + 33.94 \\ = 99.94 \: ft`