Question

How do I solve for what is sin A for the triangle shown

Answer 1

Option a:

sin A for the triangle is
`(3)/(5)`.

Solution:

The given triangle is a right triangle.

The adjacent side to angle A is AC.

The opposite side to angle A is BC.

Hypotenuse is AB.

AC = 8, BC = 6 and AB = 10.

Using trigonometric ratio formulas,

`$\sin \theta=\frac{\text { Opposite side }}{\text { Hypotenuse }}`

`$\sin A=(BC)/(AB)`

`$\sin A=(6)/(10)`

Divide both numerator and denominator by 2, we get

`$\sin A=(6/2)/(10/ 2)`

`$\sin A=(3)/(5)`

Hence sin A for the triangle is
`(3)/(5)`.

Option a is the correct answer.