Question

When you hit a .27 kg volleyball the contact time is 50 ms and the average force is 125 N. If you serve the volleyball (from rest) sending it up at 30 degrees above the horizontal, what is the

A) vertical component of the momentum of the volleyball in kgm/s?
B) horizontal component of the momentum of the volleyball in kgm/s?

Answer 1

The vertical component of the momentum of the volleyball is -0.49 kgm/s and the horizontal component is 38.93 kgm/s.

Step-by-step explanation:

To find the vertical component of the momentum, we need to first find the vertical velocity of the volleyball. We can use the equation:

vf = vi + at

The initial vertical velocity is 0 m/s since the volleyball was sent up from rest. The final velocity can be found using the equation:

vf = vi + gt

where g is the acceleration due to gravity. Plugging in the values and solving for vf, we get:

vf = 0 + (-9.8 m/s^2)(0.05 s)

vf = -0.49 m/s

Since the downward direction is considered negative, the vertical component of the momentum is -0.49 kgm/s.

To find the horizontal component of the momentum, we can use the equation:

p = mv

where p is the momentum, m is the mass of the volleyball, and v is the horizontal velocity. The horizontal velocity can be found using:

vx = v * cos(theta)

where theta is the angle above the horizontal. Plugging in the values, we get:

vx = 45 m/s * cos(30 degrees)

vx = 38.93 m/s

Therefore, the horizontal component of the momentum is 38.93 kgm/s.