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a lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block?(unit=kg) IM GIVING 30 POINTS FOR THE CORRECT ANSWER

User Chowey
by
4.6k points

2 Answers

4 votes

Answer: 0.5654

Step-by-step explanation:

User JonathanV
by
4.3k points
2 votes

Answer:

577g

Step-by-step explanation:

Given parameters:

Temperature change = 5.9°C

Amount of heat lost = 427J

Unknown:

Mass of the block = ?

Solution:

The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.

H = m c Ф

H is the heat capacity

m is the mass of the block

c is the specific heat capacity

Ф is the temperature change

Specific heat capacity of lead is 0.126J/g°C

m = H / m Ф

m =
(427)/(0.126 x 5.9) = 577g

Mass of the lead block is 577g

User Tamal Samui
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4.2k points