Question

Diagram shows the velocity time graph for a particle moving in 16 seconds.

Find
a)The maximum acceleration of the particle

b)The deceleration of the particle

c)The total distance travelled by the particle

d)The average velocity of the particle
​

Answer 1

The detailed calculations are shown below;

Step-by-step explanation:

a)The maximum acceleration of the particle:

It is seen that the maximum change in velocity is at the time between 8s to 10s.

Maximum acceleration:
`(V)/(t)`

=
`(20)/(2)`

= 10 m/
`s^(2)`

b) The deceleration of the particle

The velocity of particle is decreased after 10s so,

deceleration = -
`(40)/(6)`

= - 6.67 m/
`s^(2)`

c)The total distance traveled by the particle = Area under the curve

=
`(1)/(2)`* 4*20 + 4*20 +
`(1)/(2)`* 2*20+ 2*20+
`(1)/(2)`* 40*16

= 290 m

d)The average velocity of the particle =
`(Area under the curve)/(Total time)`

=
`(290)/(16)`

= 18.12 m/s