Question

When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coefficient of volume expansion? PLEASE HELPPP MEEEEE

Answer 1

8.1

Step-by-step explanation:

Answer 2

Coefficient of volume expansion is 8.1 ×10⁻⁴ C⁻¹.

Step-by-step explanation:

The volume expansion of a liquid is given by ΔV,

ΔV = α V₀ ΔT

ΔT = change in temperature = 48.5° C

α = coefficient of volume expansion =?

V₀ = initial volume = 2.35 m³

We need to find α , by plugin the given values in the equation and by rearranging the equation as,

`\alpha=\frac{\Delta \mathrm{V}}{\mathrm{V}_(0) \Delta \mathrm{T}}=(0.0920)/(2.35 * 48.5)=0.00081`

= 8.1 ×10⁻⁴ C⁻¹.