Question

A 265 g mass attached to a horizontal spring oscillates at a frequency of 3.40 Hz . At t =0s, the mass is at x= 6.20 cm and has vx =− 35.0 cm/s . Determine The phase constant.

Answer 1

The phase constant is 7.25 degree

Step-by-step explanation:

given data

mass = 265 g

frequency = 3.40 Hz

time t = 0 s

x = 6.20 cm

vx = - 35.0 cm/s

solution

as phase constant is express as

y = A cosФ ..............1

here A is amplitude that is =
`\sqrt{((v_x)/(\omega ))^2+y^2 }` =
`\sqrt{((35)/(2* \pi * y))^2+6.2^2 }` = 6.25 cm

put value in equation 1

6.20 = 6.25 cosФ

cosФ = 0.992

Ф = 7.25 degree

so the phase constant is 7.25 degree