Question

The diffraction phenomenon can be observed whenever the wavelength is comparable in magnitude to the size of the slit opening. To be "diffracted," how fast must a person weighing 84 kg move through a door 1 m wide

Answer 1

Velocity,
`v=7.89*10^(-36)m/s`

Step-by-step explanation:

Diffraction will only occur when the wavelength,
`\lambda`, is comparable in size to the slit opening. Given the,
`\lambda=1m,`,and mass of the person as
`84kg`, we can apply

De-Broglie equation, to obtain the velocity.

`\lambda=(h)/(mv)\\v=(6.626*10^(-34)Js)/(84kg*1m)\\v=7.89*10^(-36)m/s`

The velocity of the person is
`7.89*10^(-36)m/s`