The ratio of the circumference to the diameter is
![3.14:1](https://img.qammunity.org/2021/formulas/mathematics/college/ofdifb0khr9itpc6vthyo8dsd8hbzq2nwh.png)
Step-by-step explanation:
It is given that a circle with diameter of 4 cm and circumference is 12.57 cm
The ratio of the circumference to the diameter is
![12.57:4](https://img.qammunity.org/2021/formulas/mathematics/college/af5ftg6n3efp85jie3er2hce62so7y6ml5.png)
We need to determine the ratio of the circumference to the diameter.
Let us substitute the values in the circumference of the circle formula.
Thus, we have,
![C=\pi d](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4889gpkyupa1tbplhz7m9qvf8421d3sdxn.png)
![\pi = (C)/(d)](https://img.qammunity.org/2021/formulas/mathematics/college/pcxy0ams3svuek72ikjxqfyrcwr2afwtdp.png)
where C is the circumference and d is the diameter.
Thus, we get,
![\pi=(12.57)/(4)](https://img.qammunity.org/2021/formulas/mathematics/college/wgs1nuszraimfe8b5l6hxy6ebwjuu8wnhk.png)
![\pi=3.1425](https://img.qammunity.org/2021/formulas/mathematics/college/r1f5jvoavrpca2srf9gfbz84rp9dncfpfh.png)
(app.)
Thus, the ratio is the circumference to the diameter is
![3.14:1](https://img.qammunity.org/2021/formulas/mathematics/college/ofdifb0khr9itpc6vthyo8dsd8hbzq2nwh.png)