Answer: The confidence interval would be (120.6, 159.4).
Explanation:
Since we have given that
n = 200
mean =
Standard deviation =
![\sigma=25\ mm](https://img.qammunity.org/2021/formulas/mathematics/college/sz4zr5ftt6oyovczc3bav7qm1uowdkzqm5.png)
At 95% confidence interval, z = 1.96
So, 95% confidence interval would be
![\bar{x}\pm z(\sigma)/(√(n))\\\\=140\pm 1.96* (140)/(√(200))\\\\=140\pm 19.40\\\\=(140-19.4,140+19.4)\\\\=(120.6,159.4)](https://img.qammunity.org/2021/formulas/mathematics/college/hso1c59puasfd92x35gukt8fs4zxhy8sg4.png)
Hence, the confidence interval would be (120.6, 159.4).