Question

The same potential difference is applied across two wires. Wire A carries twice thecurrent of wire B. If the resistance of wire B isR, what is the resistance of wire A?

Answer 1

R / 2

Step-by-step explanation:

According to Ohm law, the current flowing within the resistor is the ratio between the potential difference and the resistance:

`I = (V)/(R)`

So if wire A carries twice the current of wire B, while their potential is the same then:

`I_A = 2I_B`

`(V)/(R_A) = (2V)/(R_B)`

`R_B = 2R_A`

`R_A = R_B / 2 = R / 2`