Answer:
12.8 g of
must be withdrawn from tank
Step-by-step explanation:
Let's assume
gas inside tank behaves ideally.
According to ideal gas equation-

where P is pressure of
, V is volume of
, n is number of moles of
, R is gas constant and T is temperature in kelvin scale.
We can also write,

Here V, T and R are constants.
So,
ratio will also be constant before and after removal of
from tank
Hence,

Here,
and

So,

So, moles of
must be withdrawn = (0.66 - 0.26) mol = 0.40 mol
Molar mass of
= 32 g/mol
So, mass of
must be withdrawn =
