Question

What is the equation of a line with points (16,-4) and (-32-10) Oy - 4= 1 (x - 16) Oy+4= 1 (x – 16) Oy - 10 = 3 (x – 32) O y + 10 = 1 (x + 32)​

Answer 1

Points

• (16,-4)
• (-32,-10)

Equation of line in two points form

`\\ \sf\longmapsto y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1)`

`\\ \sf\longmapsto y+10=(-10+4)/(-32-16)(x+32)`

`\\ \sf\longmapsto y+10=(-6)/(-48)(x+32)`

`\\ \sf\longmapsto y+10=(1)/(8)(x+32)`

Option D

Answer 2

• D. y + 10 = 1/8* (x + 32)

Explanation:

Use the given points to work out the equation of the line.

Find the slope:

• m = (- 10 - (-4)) / (- 32 - 16) = - 6 / - 48 = 1/8

Use (-32, - 10) and point- slope form:

• y - (- 10) = 1/8*(x - (-32))
• y + 10 = 1/8* (x + 32)

Correct choice is D