Question

A digital IC manufacturer has determined that for adequate yield, a specification on the drive current for a minimum geometry MOSFET device must be in the range from 100mA/um < k < 200mA/um. Therefore, LSL=100mA/um and USL = 200mA/um.Suppose that to yield a working IC, the transistor yield (i.e.those that pass the spec) must be 99.98%.How manystandard deviations from the mean must LSL and USLrepresent?Assume that the process mean is equal to thedesired mean

Answer 1

Answer: The standard deviation from the mean of USL and LSL is 50

Step-by-step explanation:

Since LSL= 100

USL = 200

STEP1: Find the mean value;

To find the mean, we take the average of LSL and USL.

200 + 100 = 300

Therefore;

300 ÷ 2= 150

STEP2: Find the variance;

To find the variance, we first minus the mean value from the values of ULS and LSL and then square the value

(100 - 150)^2 = 2500

(200 - 150)^2 = 2500

To get the variance

Then sum up the values and divide by the number of values which is 2

(2500+2500) ÷ 2 = 2500

STEP3 : Find the standard deviation;

Standard deviation= √variance

Standard deviation = √2500 = 50