Answer:
1x10^-2mol/L
Step-by-step explanation:
[OH-] = 1x10 ^-12 mol/L
Recall:
[H+] x [OH-] = 1x10^-14
[H+] x 1x10 ^-12 = 1x10^-14
Divide both side by 1x10 ^-12
[H+] = 1x10^-14/ 1x10 ^-12
[H+] = 0.01 = 1x10^-2mol/L
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