Question

In a particular experiment at 300 , drops from 0.0225 to 0.00669 in 190 . The rate of disappearance of for this period is ________ .

a. 4.16×10^−5
b. 8.32×10^−5
c. 1.20×10^4
d. 1.66×10^−4
e. −1.54×10^−4

Answer 1

(B) 8.32×10^-5

Step-by-step explanation:

Rate of disappearance = change in concentration/time

Initial concentration = 0.0225

Final concentration = 0.00669

Change in concentration = initial concentration - final concentration = 0.0225 - 0.00669 = 0.01581

Time = 190

Rate of disappearance = 0.01581/190 = 8.32×10^-5