Question

A seed company planted a floral mosaic of a national flag. The perimeter of the flag is 2,240 ft. Determine the flags width and length if the length is 420 ft greater than the width

Answer 1

The question is a high school level mathematics problem where students must solve for the dimensions of a flag's length and width given the perimeter and a relationship between the length and width.

Step-by-step explanation:

The subject of this question is Mathematics because it involves solving for the dimensions of a geometric shape using given perimeter and relationship information between the length and width of the shape.

To find the width and length of the flag, we will set up two equations given that perimeter (P) is the sum of twice the length (L) plus twice the width (W), thus P = 2L + 2W. Here, it's given that P = 2,240 ft and the length is 420 ft greater than the width, so L = W + 420 ft.

The two equations to solve simultaneously are:
1. 2,240 = 2L + 2W
2. L = W + 420

Substitute the second equation into the first to solve for W, then use the result to find L.

Answer 2

Answer: the length of the flag is 770ft.

The width of the flag is 350 ft

Step-by-step explanation:

Let L represent the length of the national flag.

Let W represent the width of the national flag.

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of the flag is 2,240ft. This means that 2240 = 2(L + W)

Dividing through by 2, it becomes

1120 = L + W- - - - - - - - - - - -1

if the length is 420 ft greater than the width, it means that

L = W + 420

Substituting L = W + 420 into equation 1, it becomes

1120 = W + 420 + W

2W + 420 = 1120

2W = 1120 - 420 = 700

W = 700 / 2 = 350

L = W + 420 = 350 + 420

L = 770