Answer:
The fraction is
![(6)/(13) .](https://img.qammunity.org/2021/formulas/mathematics/high-school/pu2e8p3z1l9ouyjhyh05hd9t8o83ag0rwb.png)
Explanation:
There is a data missing in the question so the complete question is below:
If 1 is added to both numerator and denominator of a fraction,the fraction become 1/2 if 8 is added to both, the fraction become 2/3 what is the fraction?
Now, to find the fraction.
Let the fraction be
![(x)/(y) .](https://img.qammunity.org/2021/formulas/mathematics/high-school/xlugo2ali8k6hews26px3vbv5to63lh0vo.png)
If 1 is added to both numerator and denominator of a fraction,the fraction become 1/2.
![(x+1)/(y+1)=(1)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/gvzjiuibyza60khxib6j6471bgiqxv7l7p.png)
By cross multiplying we get:
![2x+2=y+1](https://img.qammunity.org/2021/formulas/mathematics/high-school/2njg3cz9fx58ujlt9dxdwwijjjf9h1q9tw.png)
Subtracting both sides by
we get:
![2x+1=y](https://img.qammunity.org/2021/formulas/mathematics/high-school/pg1rbtko11y5s5kobchrriiewhlln9ucr8.png)
......(1)
Now, if 8 is added to both, the fraction become 2/3:
![(x+8)/(y+8) =(2)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/nbdq85glfsdiukw9riwmdhv1qzuemsh8rn.png)
By cross multiplying we get:
![3x+24=2y+16](https://img.qammunity.org/2021/formulas/mathematics/high-school/18ne9yqxlo4gwdop76syu17yao9h1m5ww7.png)
Subtracting both sides by 16 we get:
![3x+8=2y](https://img.qammunity.org/2021/formulas/mathematics/high-school/en7878qu7b9kruzzgnmrmuw9l2jdvudsou.png)
Substituting the value of
from equation (1) we get:
![3x+8=2(2x+1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/7iaudibna2hvwr6f4sqc0r2qcvxschmefe.png)
![3x+8=4x+2](https://img.qammunity.org/2021/formulas/mathematics/high-school/o00nt581m27i2t6mpdifageernwfd824xy.png)
Adding both sides by 2 we get:
![3x+6=4x](https://img.qammunity.org/2021/formulas/mathematics/high-school/md6p5u0vq11t8yajey4rjep40aw0j57i13.png)
Subtracting both sides by 3
we get:
![6=x](https://img.qammunity.org/2021/formulas/mathematics/middle-school/k9zhdmio6133tp0h8lbos967zqfgwvqxu3.png)
![x=6.](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5rw0kltwqln2fg7jbq8g8rko0nbcrl9giw.png)
Now, substituting the value of
in equation (1):
![y=2x+1\\y=2* 6+1\\y=12+1\\y=13.](https://img.qammunity.org/2021/formulas/mathematics/high-school/72p47e0h1xyt9ej7v6qy2a3samlqgbka37.png)
Therefore, the fraction is
![(6)/(13) .](https://img.qammunity.org/2021/formulas/mathematics/high-school/pu2e8p3z1l9ouyjhyh05hd9t8o83ag0rwb.png)