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Solve the system of linear equations by elimination.

11x−20y=28
3x+4y=36

User Ali Nauman
by
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2 Answers

13 votes
13 votes

Solve the system of linear equations by elimination.

11x−20y=28

3x+4y=36

Solve the system of linear equations by elimination. 11x−20y=28 3x+4y=36-example-1
Solve the system of linear equations by elimination. 11x−20y=28 3x+4y=36-example-2
User Davertron
by
3.0k points
15 votes
15 votes

Answer:

x = 8, y = 3.

Explanation:

11x − 20y = 28

3x + 4y = 36 multiply this equation by 5:

15x + 20y = 180

Add this new equation to the first one ( to eliminate the 20y):

26x = 208

x = 208/26 = 8.

Substitute x = 8 into the second equation:

3(8) + 4y = 36

4y = 36 - 24 = 12

y = 3.

User Seif Sallam
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2.6k points