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3 votes
A group of 8 friends (5 girls and 3 boys) plans to watch a movie, but they have only 5 tickets. How many different combinations of 5 friends could

possibly receive the tickets?
A. 13
B. 40
C. 56
D. 64

2 Answers

4 votes

Answer: C 56

Explanation:

User Ashirley
by
3.7k points
3 votes

There can be 56 possible combinations.

Explanation:

Step 1:

With 8 friends and 5 tickets, the possible combinations will be in 8C5 ways.

⇒ 8C5 = 8!/3!5! = 8 × 7 × 6/3! = 336/6 = 56

User GavinBurke
by
3.9k points