352.25 Ohms is the total inductive reactance in a parallel circuit.
Answer:
Step-by-step explanation:
As inductive reactance is defined as the product of frequency with the inductances. Since the inductors are connected in parallel, the voltage drop through each inductor will be constant. As the voltage through any parallel circuit connection is ought to be constant. But the current flow through each inductor will vary.
So Total current = I1 +I2
Since


L = (1.5*2.5)/(1.5+2.5)=0.9375
Inductive reactance is the measure of resistance offered by the inductor.

Here f = 60 Hz, L = 0.9375 H
So, inductive reactance in parallel circuit = 2×3.14×60×0.9375
Total inductive reactance in parallel circuit = 352.25 Ohm
So 352.25 Ohms is the total inductive reactance in a parallel circuit.