Answer: The amount of element X remain after 40 years is 18.75 grams
Step-by-step explanation:
We are given:
Total time period = 40 years
One half life = 10 years
Calculating the number of half lives,
![n=\frac{\text{Total time period}}{\text{One half life}}](https://img.qammunity.org/2021/formulas/chemistry/college/ave2s7wg3awbl89etcfsnoxu0isw9xv5ba.png)
![n=(40)/(10)=4](https://img.qammunity.org/2021/formulas/chemistry/college/7zq53i8x8g3dhlrm4307jlnsuoz91covr2.png)
To calculate the amount of element X after 4 half lives, we use the equation:
![a=(a_o)/(2^n)](https://img.qammunity.org/2021/formulas/chemistry/college/6lncbbgbn6g92ymjz67gyi9k7joj0sa8n5.png)
where,
a = amount of X after n-half lives
= initial amount of X = 300 g
n = number of half lives = 4
Putting values in above equation, we get:
![a=(300)/(2^4)\\\\a=18.75g](https://img.qammunity.org/2021/formulas/chemistry/college/7fng6hdeo8winpo76pnw9yqu59mc83zzdu.png)
Hence, the amount of element X remain after 40 years is 18.75 grams