Question

A simple pendulum consists of a 4.9 kg point mass hanging at the end of a 3.1 m long light string that is connected to a pivot point. Calculate the magnitude of the torque (due to the force of gravity) around this pivot point when the string makes a 3.1 ◦ angle with the vertical. The acceleration of gravity is 9.81 m/s 2 . Answer in units of N · m.

Answer 1

8.1 N-m

Step-by-step explanation:

We are given that

Mass=m=4.9 kg

Length=L=3.1 m

`\theta=3.1^(\circ)`

`g=9.8m/s^2`

We have to find the magnitude of torque (due to the force of gravity).

We know that

`\tau=mgLsin\theta`

Using the formula

`\tau=4.9* 9.8* 3.1sin3.1^(\circ)`

`\tau=8.1 N-m`

Hence, the magnitude of torque =8.1 N-m