Question

The skateboarder has a mass of 100 kg. When traveling downward from E to D, he reaches a velocity of 11 m/s. Calculate his kinetic energy at D (explain work and include units please).

(KE= ½ mv2)

Answer 1

6050 J is the kinetic energy at D

Step-by-step explanation:

In physics, the object's kinetic energy (K.E) defined as the energy it possesses during movement. It can be defined as the required work to accelerate a certain body weight in order to rest at a certain speed. When the body receives this energy as it speeds up (accelerates), it retains this energy unless speed varies. The equation is given as,

`K . E=(1)/(2) * m * v^(2)`

Where,

m - mass of an object

v - velocity of the object

Here,

Given data:

m = 100 kg

v = 11 m/s

By substituting the given values in the above equation, we get

`K . E=(1)/(2) * 100 *(11)^(2)=(1)/(2) * 100 * 121=(12100)/(2)=6050\ \mathrm{J}`