Answer: The value of k is 0.09.
Explanation:
Since we have given that
![P(t)=P(0)e^(kt)](https://img.qammunity.org/2021/formulas/mathematics/high-school/zvk34n0t686pigux8a8xnl5k4ibor14rnl.png)
Here, k is the rate ,
t is the time,
In 2004, the whooping cranes tallied 213 birds,
So, P(t)=213
It is 19 greater than 2003,
So, P(0)=213-19=194
So, substitute all the values in given expression:
![213=194e^(k.1)\\\\(213)/(194)=e^k\\\\1.098=e^k\\\\\text{Taking log on both the side}\\\\\ln 1.098=k\\\\k=0.09](https://img.qammunity.org/2021/formulas/mathematics/high-school/4gxmaohiedkazs1gwijmxhpghpmnqv238m.png)
Hence, the value of k is 0.09.