Answer:
110000000 m/s²
Step-by-step explanation:
From Newton's equation of motion,
v² = u²+2as ................... Equation 1
Where v = final velocity of the space capsule, u = initial velocity of the space capsule, a = acceleration of the space traveler, s = length of the cannon.
make a the subject of the equation,
a = (v²-u²)/2s................ Equation 2
Given: v = 220 km/s = 220000 m/s. u = 0 m/s (As the space capsule was initially at rest), s = 220 m.
Substitute into equation 2
a = (220000²-0)/(2×220)
a = 48400000000/440
a = 110000000 m/s²
Hence the unrealistic large acceleration = 110000000 m/s²