Question

The length of a rectangular court is 12 ft longer than twice the width. The perimeter of the court is 96 ft. Determine the length and width of the court.

Answer 1

28 ft x 20 ft

Explanation:

Perimeter = 2xlength+2xwidth

let's say width = w and length = 2w-12

Plug that back in: 96 = 2(2w-12)+2(w)

Solve algebraically: 96 = 4w-24+2w

96=6w-24

6w=120

w=20

Plug that back into length: 2(20)-12 = 40-12 = 28

Therefore, 28 ft for length and 20 ft for width, or 28 ft x 20 ft

Answer 2

Answer: the length is 36 ft

The width is 12 ft

Explanation:

Let L represent the length of the rectangular court.

Let W represent the width of the rectangular court.

The length of a rectangular court is 12 ft longer than twice the width. This is expressed as

L = 2W + 12

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of the court is 96 ft. This means that

2(L + W) = 96

L + W = 96/2

L + W = 48 - - - - - - - - - - 1

Substituting L = 2W + 12 into equation 1, it becomes

2W + 12 + W = 48

3W = 48 - 12

3W = 36

W = 36/3

W = 12

L = 2 × 12 + 12

L = 24 + 12

L = 36