Answer:
The answer to your question is 17.26 g of NaNO₃
Step-by-step explanation:
Data
mass of NaNO₃ = ?
volume = 625 ml
concentration = 0.325 M
Process
1.- Convert volume to liters
1000 ml ----------------- 1 L
625 ml ---------------- x
x = 625 / 1000
x = 0.625 L
2.- Find the moles of NaNO₃
Molarity = moles / volume
solve for moles
moles = Molarity x volume
substitution
moles = 0.325 x 0.625
simplification
moles = 0.203
3.- Convert moles to grams
molar mass of NaNO₃ = 23 + 14 + (16 x 3)
= 85 g
85 g ------------------ 1 mol
x ------------------ 0.203
x = (0.203 x 85) / 1
x = 17.26 g