Question

Jaya has a 10 square piece of origami paper. If she folds the square into 4 equal triangle s, what will be the area of each triangle?

Answer 1

Area of triangle =
`(s^(2) )/(2)`

Explanation:

Jaya has 10 square pieces of origami paper , she folds the square into 4 equal triangle s. We have, a triangle with side s . Now, in square if we see , length of diagonal is 2s . Let side of square is a ∴ By Pythagoras theorem ,
`Diagonal^(2) = a^(2) + a^(2)`

`(2s)^(2) = 2a^(2)`

`4s^(2) = 2a^(2)`

`a = √(2) s` .

Now, Area of triangle =
`(1)/(2) * \text { base } * \text { height }`

base =
`√(2)s` and height =
`(√(2) s)/(2)`

∴Area of triangle =
`(1)/(2)\\` ×
`√(2)s` ×
`(√(2) s)/(2)`

Area of triangle =
`(s^(2) )/(2)`