Question

2FeCl3 + 3Mg → 3MgCl2 + 2Fe

If 4.5 moles of Mg react, how many moles of FeCl3 will be
produced?
A. 3 moles
B. 4.5 mole
C. 2 moles
D. 9 moles

Answer 1

`\large \boxed{\text{A. 3.0 mol}}`

Step-by-step explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

2FeCl₃ + 3Mg ⟶ 3MgCl₂ + 2Fe

n/mol: 4.5

2 mol of FeCl₃ react with 3 mol of Mg

`\text{Moles of FeCl}_(3) = \text{4.5 mol Mg}* \frac{\text{2 mol FeCl}_(3)}{\text{3 mol Mg}}= \textbf{3.0 mol Mg}\\\\\text{The reaction will need $\large \boxed{\textbf{3.0 mol of Mg}}$}`