Question

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Answer 1

a = 6.2

Solution:

Given ABC is triangle.

AC = b = 8, BA = c = 11, ∠A = 32.2°

BC = a

To find the length of a:

Law of cosines:

`a^(2)=b^(2)+c^(2)-2 b c \cdot \cos A`

`a^(2)=8^2+11^(2)-2 * 8 * 11 \cdot \cos 32.2^\circ`

`a^(2)=64+121-174 \cdot \cos 32.2^\circ`

`a^(2)=185-174 (0.8461)`

`a^(2)=185-147.221`

`a^(2)=37.779`

Taking square root on both sides of the equation.

a = 6.1464

a = 6.2

The length of BC is 6.2.